CONDITION satisfied⇒ x2 + 1/x2Put x = 1⇒ 1 + 1⇒ 2Detailed METHOD: ⇒ x + 1/x = 2AS we know,⇒ x2 + 1/x2 = (x + 1/x)2 – 2⇒ x2 + 1/x2 = 22 – 2 = 4 – 2 = 2

"> CONDITION satisfied⇒ x2 + 1/x2Put x = 1⇒ 1 + 1⇒ 2Detailed METHOD: ⇒ x + 1/x = 2AS we know,⇒ x2 + 1/x2 = (x + 1/x)2 – 2⇒ x2 + 1/x2 = 22 – 2 = 4 – 2 = 2

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If x + 1/x = 2, then find the value of x2 + 1/x2.

General Aptitude Algebra in General Aptitude . 3 months ago

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⇒ x + 1/x = 2Let x = 1, then CONDITION satisfied⇒ x2 + 1/x2Put x = 1⇒ 1 + 1⇒ 2Detailed METHOD: ⇒ x + 1/x = 2AS we know,⇒ x2 + 1/x2 = (x + 1/x)2 – 2⇒ x2 + 1/x2 = 22 – 2 = 4 – 2 = 2

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