X = √6 + √5Formula USED: (a - b)2 = a2 + B2 - 2abCalculation:x = √6 + √5⇒ 1/x = √6 - √5 ⇒ x - 1/x = 2√5⇒ (x - 1/x)2 = (2√5)2⇒ x2 + 1/x2 - 2 = 20∴ The VALUE of x2 + 1/x2 - 2 is 20.

"> X = √6 + √5Formula USED: (a - b)2 = a2 + B2 - 2abCalculation:x = √6 + √5⇒ 1/x = √6 - √5 ⇒ x - 1/x = 2√5⇒ (x - 1/x)2 = (2√5)2⇒ x2 + 1/x2 - 2 = 20∴ The VALUE of x2 + 1/x2 - 2 is 20.

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If x = √6 + √5, then \({x^2} + \frac{1}{{{x^2}}} - 2 = \)

General Aptitude Algebra in General Aptitude . 8 months ago

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Given: X = √6 + √5Formula USED: (a - b)2 = a2 + B2 - 2abCalculation:x = √6 + √5⇒ 1/x = √6 - √5 ⇒ x - 1/x = 2√5⇒ (x - 1/x)2 = (2√5)2⇒ x2 + 1/x2 - 2 = 20∴ The VALUE of x2 + 1/x2 - 2 is 20.

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