REMAINS unchangedAnd p ∝ 1/r when q remains unchangedCalculation:p ∝ q and p ∝ 1/rThen, p = k(q/r)Putting the VALUE of r = 4, p = 10 and q = 8 then10 = k(8/4)⇒ k = 5Now, When p = 15 and q = 9Then, p = k(q/r)⇒ 15 = 5 × (9/r)⇒ r = (5 × 9)/15⇒ r = 3

"> REMAINS unchangedAnd p ∝ 1/r when q remains unchangedCalculation:p ∝ q and p ∝ 1/rThen, p = k(q/r)Putting the VALUE of r = 4, p = 10 and q = 8 then10 = k(8/4)⇒ k = 5Now, When p = 15 and q = 9Then, p = k(q/r)⇒ 15 = 5 × (9/r)⇒ r = (5 × 9)/15⇒ r = 3

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p ∝ q when ‘r’ remains unchanged and p ∝ 1/r when q remains unchanged. If r = 4 when p = 10 and q = 8, what is the value of r when p = 15 and q = 9?

General Aptitude Algebra in General Aptitude 10 months ago

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Given:P ∝ q when ‘r’ REMAINS unchangedAnd p ∝ 1/r when q remains unchangedCalculation:p ∝ q and p ∝ 1/rThen, p = k(q/r)Putting the VALUE of r = 4, p = 10 and q = 8 then10 = k(8/4)⇒ k = 5Now, When p = 15 and q = 9Then, p = k(q/r)⇒ 15 = 5 × (9/r)⇒ r = (5 × 9)/15⇒ r = 3

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