Show that the data given below is in agreement with the law of constant composition
`{:("Exp. No.","Mass of iron","Mass of iron oxide"),("(i)","2.7812 g","3.9756 g"),("(ii)","3.0499 g","4.3596 g"),("(iii)","4.4913 g","6.4202 g"):}`

General Awareness MOLE-CONCEPT IN GENERAL AWARENESS 2 years ago

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Experiement No. (i)
Mass of iron = 2.7812 g , Mass of iron oxide = 3.9756 g
Percentage of iron `= ((2.7812g))/((3.9756g))xx100=70%`
Percentage of oxygen `= 100 - 70 = 30 %`
Experiment No. (ii)
Mass of iron = 3.0499 , Mass of iron oxide = 4.3596 g
Percentage of iron `= ((3.0499))/((4.3596g))xx100=70%`
Percentage of oxygen `= 100-70=30%`
Experiment No. (iii)
Mass of iron = 4.4913 g , Mass iron oxide = 6.4202 g
Percentage of iron `= ((4.4913g))/((6.42402g))xx100=70%`
Percentage of oxygen `= 100 - 70 = 30 %`
Since the ratio by weights of iron and oxygen in the three oxides is the same, the data is according to Law of constant Composition.

Posted on 06 Oct 2022, this text provides information on General Awareness related to MOLE-CONCEPT IN GENERAL AWARENESS. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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