The speed of sound in human tissue is of the order of `1500 m//s`. A `3.5 MHz` probe is used for an ultrasonic procedure.
(a) If the effective physical depth of the ultrasound is `250` wavelengths, what is the physical depth in metres ?
(b) What is the time lapse for the ultrasound to make a round trip if reflected from an object at the effective depth ?
(c ) The smallest detail capable of being detected is of the order of one wavelength of the ultrasound. What would this be ?

General Awareness SOUND IN GENERAL AWARENESS 2 years ago

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(a) `lamda = (v)/(v) = (1500 m//s)/(3.5 xx 10^6 m) = 428.6 xx 10^6 m`
Physical depth of ultrasound in metres `= 200 lamda = 250 (428.6 xx 10^6 m) = 0.10715 m`
(b) `t = (s)/(v) = (2 xx 0.10715 m)/(1500 m//s) = 0.000143 s = 1.43 xx 10^-4 s`
( c) The smallest possible detail capable of being detected `= lamda = 428.6 xx 10^-6 m = 4.29 xx 10^-4 m`.

Posted on 06 Oct 2022, this text provides information on General Awareness related to SOUND IN GENERAL AWARENESS. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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