B)2 = a2 + b2 + 2absin α = 1/cosec αcos α = 1/sec αsin2 α + cos2 α = 1cosec2 α = 1 + cot2 αsec2 α = 1 + TAN2 αCalculation:(sin α + cosec α)2 + (COS α + sec α)2⇒ sin2 α + COSEC2 α + 2sin α.cosec α + cos2 α + sec2 α + 2cos α.sec α (∵ (a + b)2 = a2 + b2 + 2ab)⇒ sin2 α + cosec2 α + 2 + cos2 α + sec2 α + 2 (∵ sin α = 1/cosec α and cos α = 1/sec α)⇒ (sin2 α + cos2 α) + 1 + cot2 α + 1 + tan2 α + 4 (∵ sin2 α + cos2 α = 1; cosec2 α = 1 + cot2 α and sec2 α = 1 + tan2 α)⇒ tan2 α + cot2 α + 7∴ The required answer is tan2 α + cot2 α + 7.