CONCEPT:If n batteries with each having an emf ‘V’ and interval resistance ‘R’ are connected in SERIES, the equivalent circuit can be drawn as:Application:Given 2 ROWS of cellsLet each ROW has n cellsGiven V = 2.1 V, and R = 0.5 ΩApplying KVL, we get:nR(3) – nV + 6(0.7) = 0\(\frac{3}{2}n - 2.1\;n + 4.2 = 0\)0.6 n = 4.2n = 7∴ The minimum no. of cells will be:= n(1st row) + n(2nd row) = 14