CIRCLE X2 + y2 = a2.(h, k) will satisfy the EQUATION x2 + y2 = a2.⇒ h2 + k2 = a2 The equation of the chord of the contact of tangents drawn from the point P(h, k) to the circle x2 + y2 = b2 will behx + ky = b2 Perpendicular distance of this tangent from the centre of the circle x2 + y2 = c2 will be equal to the RADIUS of the circle.\(⇒ |{-b^2 \over \sqrt{h^2+k^2}}| = c\)\(⇒ |{-b^2 \over a}| = c\)\(⇒ b^2 = ac\)Comparing it with BP = amcn ⇒ p = 2, m = n = 1∴ m + n + p + 3 = 1 + 1 + 2 + 3 = 7