OCCURS at centre.∴ Umax = Centre–line velocity For laminar flow, \({U_{avg}} = \frac{{{U_{max}}}}{2} \)Discharge (Q) = Area × Average velocityCalculation:Given:Pipe diameter, d = 0.04 m, Umax = Centre–line velocity = 1.5 m/s\({U_{avg}} = \frac{{{U_{max}}}}{2} =\frac{{1.5}}{{2}}\RIGHTARROW 0.75\) m/sDischarge (Q) = Area × Average velocity = \( \frac{\pi }{4} \times {\left( {0.04} \RIGHT)^2} \times 0.75 =\frac{{3\pi}}{{10000}}\) m3/s.

"> OCCURS at centre.∴ Umax = Centre–line velocity For laminar flow, \({U_{avg}} = \frac{{{U_{max}}}}{2} \)Discharge (Q) = Area × Average velocityCalculation:Given:Pipe diameter, d = 0.04 m, Umax = Centre–line velocity = 1.5 m/s\({U_{avg}} = \frac{{{U_{max}}}}{2} =\frac{{1.5}}{{2}}\RIGHTARROW 0.75\) m/sDischarge (Q) = Area × Average velocity = \( \frac{\pi }{4} \times {\left( {0.04} \RIGHT)^2} \times 0.75 =\frac{{3\pi}}{{10000}}\) m3/s.

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The discharge in m3/s for laminar flow through a pipe of diameter 0.04 m having a centre line velocity of 1.5 m/s.

General Knowledge General Awareness in General Knowledge . 6 months ago

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Concept:For laminar flow, Maximum velocity OCCURS at centre.∴ Umax = Centre–line velocity For laminar flow, \({U_{avg}} = \frac{{{U_{max}}}}{2} \)Discharge (Q) = Area × Average velocityCalculation:Given:Pipe diameter, d = 0.04 m, Umax = Centre–line velocity = 1.5 m/s\({U_{avg}} = \frac{{{U_{max}}}}{2} =\frac{{1.5}}{{2}}\RIGHTARROW 0.75\) m/sDischarge (Q) = Area × Average velocity = \( \frac{\pi }{4} \times {\left( {0.04} \RIGHT)^2} \times 0.75 =\frac{{3\pi}}{{10000}}\) m3/s.

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Posted on 27 Nov 2024, this text provides information on General Knowledge related to General Awareness in General Knowledge. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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