CONCEPT:The following circuit shown is a system with line to ground fault.Here, Va = 0, Ib = 0, Ic = 0Now, \({I_{a1}} = \frac{1}{3}\LEFT( {{I_a} + k{I_b} + {k^2}{I_c}} \right)\)\({I_{A2}} = \frac{1}{3}\left( {{I_a} + {k^2}{I_b} + k{I_c}} \right)\)\({I_{a0}} = \frac{1}{3}\left( {{I_a} + {I_b} + {I_c}} \right)\)By substituting Ib and Ic values,\({I_{a1}} = {I_{a2}} = {I_{a0}} = \frac{{{I_a}}}{3}\)Hence in LG faults, all of the three COMPONENTS la0, la1 and la2 are equalApplication:IPositive = - j0.91 P.U.INegative = -j0.91 P.U.IZero = -j0.91 P.U.As all the sequence currents are equal, the fault is SINGLE line to ground fault. "> CONCEPT:The following circuit shown is a system with line to ground fault.Here, Va = 0, Ib = 0, Ic = 0Now, \({I_{a1}} = \frac{1}{3}\LEFT( {{I_a} + k{I_b} + {k^2}{I_c}} \right)\)\({I_{A2}} = \frac{1}{3}\left( {{I_a} + {k^2}{I_b} + k{I_c}} \right)\)\({I_{a0}} = \frac{1}{3}\left( {{I_a} + {I_b} + {I_c}} \right)\)By substituting Ib and Ic values,\({I_{a1}} = {I_{a2}} = {I_{a0}} = \frac{{{I_a}}}{3}\)Hence in LG faults, all of the three COMPONENTS la0, la1 and la2 are equalApplication:IPositive = - j0.91 P.U.INegative = -j0.91 P.U.IZero = -j0.91 P.U.As all the sequence currents are equal, the fault is SINGLE line to ground fault. ">

The following sequence currents were recorded in a power system under a fault condition:IPositive = -j0.91 P.U.INegative = -j0.91 P.U.IZero = -j0.91 P.U.The fault is:

General Knowledge General Awareness in General Knowledge 8 months ago

  107   0   0   0   0 tuteeHUB earn credit +10 pts

5 Star Rating 1 Rating
CONCEPT:The following circuit shown is a system with line to ground fault.Here, Va = 0, Ib = 0, Ic = 0Now, \({I_{a1}} = \frac{1}{3}\LEFT( {{I_a} + k{I_b} + {k^2}{I_c}} \right)\)\({I_{A2}} = \frac{1}{3}\left( {{I_a} + {k^2}{I_b} + k{I_c}} \right)\)\({I_{a0}} = \frac{1}{3}\left( {{I_a} + {I_b} + {I_c}} \right)\)By substituting Ib and Ic values,\({I_{a1}} = {I_{a2}} = {I_{a0}} = \frac{{{I_a}}}{3}\)Hence in LG faults, all of the three COMPONENTS la0, la1 and la2 are equalApplication:IPositive = - j0.91 P.U.INegative = -j0.91 P.U.IZero = -j0.91 P.U.As all the sequence currents are equal, the fault is SINGLE line to ground fault.

Posted on 07 Dec 2024, this text provides information on General Knowledge related to General Awareness in General Knowledge. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

Take Quiz To Earn Credits!

Turn Your Knowledge into Earnings.

tuteehub_quiz

Tuteehub forum answer Answers

Post Answer

No matter what stage you're at in your education or career, TuteeHub will help you reach the next level that you're aiming for. Simply,Choose a subject/topic and get started in self-paced practice sessions to improve your knowledge and scores.