LENGTH of RECTANGLE = 25%Formula usedArea of rectangle = length × breadthCalculationLet the length of the rectangle be 'X' and breadth be 'y'Area of rectangle(A) = x × yAfter decreasing length by 25%Length = x + 25% of x = x + 0.25x = 1.25xArea remains same ⇒ x × y = 1.25x × breadth⇒ breadth = y/1.25⇒ 4y/5 = 0.8y∴ DECREASE in breadth = y - 0.8y = 0.2y = 20%

"> LENGTH of RECTANGLE = 25%Formula usedArea of rectangle = length × breadthCalculationLet the length of the rectangle be 'X' and breadth be 'y'Area of rectangle(A) = x × yAfter decreasing length by 25%Length = x + 25% of x = x + 0.25x = 1.25xArea remains same ⇒ x × y = 1.25x × breadth⇒ breadth = y/1.25⇒ 4y/5 = 0.8y∴ DECREASE in breadth = y - 0.8y = 0.2y = 20%

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The length of a rectangle is increased by 25%. By what percent of the breadth to be decreased to maintain the same area?

General Knowledge General Awareness in General Knowledge . 7 months ago

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GivenIncrease in LENGTH of RECTANGLE = 25%Formula usedArea of rectangle = length × breadthCalculationLet the length of the rectangle be 'X' and breadth be 'y'Area of rectangle(A) = x × yAfter decreasing length by 25%Length = x + 25% of x = x + 0.25x = 1.25xArea remains same ⇒ x × y = 1.25x × breadth⇒ breadth = y/1.25⇒ 4y/5 = 0.8y∴ DECREASE in breadth = y - 0.8y = 0.2y = 20%

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Posted on 25 Nov 2024, this text provides information on General Knowledge related to General Awareness in General Knowledge. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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