STAGE and then adding them together to get the TOTAL number of MUX used, i.e.:1st stage \(= \frac{{16}}{4} = 4\)2nd stage \(\; = \frac{4}{4} = 1\)The sum will give the total number of MUX required to implement 16 × 1 multiplexer using 4 × 1, i.e.n = 4 + 1 = 5Given MUXTo be implementedRequired2 : 116 : 18 + 4 + 2 + 1 = 154 : 116 : 14 + 1 = 54 : 164 : 118 + 4 + 1 = 218 : 164 : 18 + 1 = 98 : 1256 : 132 + 4 + 1 = 37