TWO equation,√2 x + √5 y = 0√6 x + √15 y = 0Concept used:Two equation a1x + b1y = 0; and a2x + B2Y = 0IF (A1/a2) = (b1/b2), then equations have infinite solutionsGiven:√2 x + √5 y = 0√6 x + √15 y = 0Here, a1 = √2, b1 = √5 and a2 = √6, b2 = √15According to the concept,(a1/a2) = (b1/b2)⇒ a1/a2 = √2/√6 = 1/3 ----(1)⇒ b1/b2 = √5/√15 = 1/3 ----(2)From equation (1) and (2), we geta1/a2 = b1/b2∴ The equations have infinite solutions.

"> TWO equation,√2 x + √5 y = 0√6 x + √15 y = 0Concept used:Two equation a1x + b1y = 0; and a2x + B2Y = 0IF (A1/a2) = (b1/b2), then equations have infinite solutionsGiven:√2 x + √5 y = 0√6 x + √15 y = 0Here, a1 = √2, b1 = √5 and a2 = √6, b2 = √15According to the concept,(a1/a2) = (b1/b2)⇒ a1/a2 = √2/√6 = 1/3 ----(1)⇒ b1/b2 = √5/√15 = 1/3 ----(2)From equation (1) and (2), we geta1/a2 = b1/b2∴ The equations have infinite solutions.

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The solutions of system of equations√2 x + √5 y = 0, √6 x + √15 y = 0 are

General Knowledge General Awareness in General Knowledge 8 months ago

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Given:We have TWO equation,√2 x + √5 y = 0√6 x + √15 y = 0Concept used:Two equation a1x + b1y = 0; and a2x + B2Y = 0IF (A1/a2) = (b1/b2), then equations have infinite solutionsGiven:√2 x + √5 y = 0√6 x + √15 y = 0Here, a1 = √2, b1 = √5 and a2 = √6, b2 = √15According to the concept,(a1/a2) = (b1/b2)⇒ a1/a2 = √2/√6 = 1/3 ----(1)⇒ b1/b2 = √5/√15 = 1/3 ----(2)From equation (1) and (2), we geta1/a2 = b1/b2∴ The equations have infinite solutions.

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Posted on 27 Nov 2024, this text provides information on General Knowledge related to General Awareness in General Knowledge. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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