4 : 7In both the ratios, the common term is ‘y’. MAKE the value with respect to ‘y’ same in both the ratioMultiply both numerator and denominator on other side of the ratio (x : y) with 4 and of ratio (y : z) with 5, we GETX : y = (3 × 4) : (5 × 4), y : z = (4 × 5) : (7 × 5)⇒ x : y = 12 : 20, y : z = 20 : 35Combining both the ratios we get, x : y : z = 12 : 20 : 35Let x = 12k, y = 20k, z = 35kGiven the sum, (12k + 20k + 35k) = 67⇒ k = 1So, x = 12, y = 20, z = 35∴ Second NUMBER = 20

"> 4 : 7In both the ratios, the common term is ‘y’. MAKE the value with respect to ‘y’ same in both the ratioMultiply both numerator and denominator on other side of the ratio (x : y) with 4 and of ratio (y : z) with 5, we GETX : y = (3 × 4) : (5 × 4), y : z = (4 × 5) : (7 × 5)⇒ x : y = 12 : 20, y : z = 20 : 35Combining both the ratios we get, x : y : z = 12 : 20 : 35Let x = 12k, y = 20k, z = 35kGiven the sum, (12k + 20k + 35k) = 67⇒ k = 1So, x = 12, y = 20, z = 35∴ Second NUMBER = 20

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The sum of three numbers is 67. If the ratio of the first number to the second number is 3 : 5 and that of the second number to the third number is 4 : 7, then what is the second number?

General Knowledge General Awareness in General Knowledge . 6 months ago

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Let the three numbers be x, y, zGiven x : y = 3 : 5, y : z = 4 : 7In both the ratios, the common term is ‘y’. MAKE the value with respect to ‘y’ same in both the ratioMultiply both numerator and denominator on other side of the ratio (x : y) with 4 and of ratio (y : z) with 5, we GETX : y = (3 × 4) : (5 × 4), y : z = (4 × 5) : (7 × 5)⇒ x : y = 12 : 20, y : z = 20 : 35Combining both the ratios we get, x : y : z = 12 : 20 : 35Let x = 12k, y = 20k, z = 35kGiven the sum, (12k + 20k + 35k) = 67⇒ k = 1So, x = 12, y = 20, z = 35∴ Second NUMBER = 20

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