4 : 7In both the ratios, the common term is ‘y’. MAKE the value with respect to ‘y’ same in both the ratioMultiply both numerator and denominator on other side of the ratio (x : y) with 4 and of ratio (y : z) with 5, we GETX : y = (3 × 4) : (5 × 4), y : z = (4 × 5) : (7 × 5)⇒ x : y = 12 : 20, y : z = 20 : 35Combining both the ratios we get, x : y : z = 12 : 20 : 35Let x = 12k, y = 20k, z = 35kGiven the sum, (12k + 20k + 35k) = 67⇒ k = 1So, x = 12, y = 20, z = 35∴ Second NUMBER = 20