2X + 2 × 27x/ (x - 1) = 9⇒ 2x + 2 × 33x/ (x - 1) = 32⇒ 2x + 2 = 3[2 - {(3x/x - 1)}]⇒ 2x + 2 = 3[-(x + 2)/(x - 1)]TAKING log⇒ (x + 2)log2 = -[(x + 2)/(x - 1)]log3⇒ x - 1 = -(log3/log2)⇒ x = 1 - (log3/log2)And(x + 2) = 0 ⇒ x = -2∴ Roots of the equation = -2, 1 - (log3/log2) "> 2X + 2 × 27x/ (x - 1) = 9⇒ 2x + 2 × 33x/ (x - 1) = 32⇒ 2x + 2 = 3[2 - {(3x/x - 1)}]⇒ 2x + 2 = 3[-(x + 2)/(x - 1)]TAKING log⇒ (x + 2)log2 = -[(x + 2)/(x - 1)]log3⇒ x - 1 = -(log3/log2)⇒ x = 1 - (log3/log2)And(x + 2) = 0 ⇒ x = -2∴ Roots of the equation = -2, 1 - (log3/log2) ">
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What are the roots of the equation 2x + 2 × 27x/x - 1 = 9?

General Knowledge General Awareness in General Knowledge 8 months ago

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2X + 2 × 27x/ (x - 1) = 9⇒ 2x + 2 × 33x/ (x - 1) = 32⇒ 2x + 2 = 3[2 - {(3x/x - 1)}]⇒ 2x + 2 = 3[-(x + 2)/(x - 1)]TAKING log⇒ (x + 2)log2 = -[(x + 2)/(x - 1)]log3⇒ x - 1 = -(log3/log2)⇒ x = 1 - (log3/log2)And(x + 2) = 0 ⇒ x = -2∴ Roots of the equation = -2, 1 - (log3/log2)
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Posted on 08 Dec 2024, this text provides information on General Knowledge related to General Awareness in General Knowledge. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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