ANSWER is option 3 i.e., 0.365.Given- \(P^H = 2\) in \(gL^{-1}\) Given - Molar mass of Hydrochloric acid = 36.5 g.Please note that HCl is a very strong acid. It would completely DISSOCIATE in the aqueous solution. It would give H3O and Chlorine.It means that H and Cl are dissociated in the aqueous solution. We know that pH= - log H+ (pH is the negative log of H+ concentration).It can be written as -2 = log (H+)ANTILOG (-2) = H+ = .01 which means there are .01 moles of hydrogen ions in 1 L of the solution.Now to find the amount of Hydrochloric acid-Amount of HCl in gm / 36.5 gm (molar mass) = 0.01 moles of HClAmount of HCl in g = 0.365