CALCULATION:Area at x = 3 will be maximum so,⇒ Area = A = \(\frac{1}{2}{\RM{\;}} \TIMES \left( {6 + 6 + 2{\rm{x}}} \right) \times \sqrt {36 - {{\rm{x}}^2}} \)⇒ A = \(\frac{1}{2}{\rm{\;}} \times \left( {12 + 3 \times 2} \right) \times \sqrt {36 - {3^2}} {\rm{\;}}\)⇒ A = 27√3 cm2 "> CALCULATION:Area at x = 3 will be maximum so,⇒ Area = A = \(\frac{1}{2}{\RM{\;}} \TIMES \left( {6 + 6 + 2{\rm{x}}} \right) \times \sqrt {36 - {{\rm{x}}^2}} \)⇒ A = \(\frac{1}{2}{\rm{\;}} \times \left( {12 + 3 \times 2} \right) \times \sqrt {36 - {3^2}} {\rm{\;}}\)⇒ A = 27√3 cm2 ">
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What is the maximum area of the trapezium?

General Knowledge General Awareness in General Knowledge 8 months ago

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CALCULATION:Area at x = 3 will be maximum so,⇒ Area = A = \(\frac{1}{2}{\RM{\;}} \TIMES \left( {6 + 6 + 2{\rm{x}}} \right) \times \sqrt {36 - {{\rm{x}}^2}} \)⇒ A = \(\frac{1}{2}{\rm{\;}} \times \left( {12 + 3 \times 2} \right) \times \sqrt {36 - {3^2}} {\rm{\;}}\)⇒ A = 27√3 cm2
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Posted on 14 Nov 2024, this text provides information on General Knowledge related to General Awareness in General Knowledge. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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