2Y = 7xy 10x + 3y = 8xy Calculation:5x + 2y = 7xy ---- (1)10x + 3y = 8xy ---- (2)Multiply EQUATION 1 by 2 and SUBTRACT equation 2 from it, we get⇒ y = 6xy⇒ x = 1/6Now, from equation 1:⇒ 5/6 + 2y = 7y/6⇒ 5y/6 = -5/6⇒ y = -1 ∴\(\left( {\frac{1}{6},\; - 1} \RIGHT)\)is the required point.