TOTAL capacitance is the sum of the individual capacitors' capacitances.\(C_{{eq}}(parallel) = {C_1} + {C_2} + {C_3} + \ldots + {C_4}\)When capacitors are connected in series, the total capacitance is less than the least capacitance connected in series.\(\frac{1}{{{C_{eq}(series)}}} = \frac{1}{{{C_1}}} + \frac{1}{{{C_2}}} + \ldots + \frac{1}{{{C_n}}}\)Calculation:For the two 6 F capacitors connected in parallel, the resultant capacitance will be:Cnet = 6 + 6 = 12 FAlso, the two 2F capacitors connected in series connection will be equivalent to a single capacitor of VALUE:Cnet = 2/2 = 1 FThe resultant circuit is drawn as:Since the 1 F and 12 F capacitors are connected in parallel, the net capacitance will be:Cnet = 1 + 12 = 13 F

"> TOTAL capacitance is the sum of the individual capacitors' capacitances.\(C_{{eq}}(parallel) = {C_1} + {C_2} + {C_3} + \ldots + {C_4}\)When capacitors are connected in series, the total capacitance is less than the least capacitance connected in series.\(\frac{1}{{{C_{eq}(series)}}} = \frac{1}{{{C_1}}} + \frac{1}{{{C_2}}} + \ldots + \frac{1}{{{C_n}}}\)Calculation:For the two 6 F capacitors connected in parallel, the resultant capacitance will be:Cnet = 6 + 6 = 12 FAlso, the two 2F capacitors connected in series connection will be equivalent to a single capacitor of VALUE:Cnet = 2/2 = 1 FThe resultant circuit is drawn as:Since the 1 F and 12 F capacitors are connected in parallel, the net capacitance will be:Cnet = 1 + 12 = 13 F

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What is the total capacitance in the given circuit?

General Knowledge General Awareness in General Knowledge 9 months ago

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Concept:When capacitors are connected in parallel, the TOTAL capacitance is the sum of the individual capacitors' capacitances.\(C_{{eq}}(parallel) = {C_1} + {C_2} + {C_3} + \ldots + {C_4}\)When capacitors are connected in series, the total capacitance is less than the least capacitance connected in series.\(\frac{1}{{{C_{eq}(series)}}} = \frac{1}{{{C_1}}} + \frac{1}{{{C_2}}} + \ldots + \frac{1}{{{C_n}}}\)Calculation:For the two 6 F capacitors connected in parallel, the resultant capacitance will be:Cnet = 6 + 6 = 12 FAlso, the two 2F capacitors connected in series connection will be equivalent to a single capacitor of VALUE:Cnet = 2/2 = 1 FThe resultant circuit is drawn as:Since the 1 F and 12 F capacitors are connected in parallel, the net capacitance will be:Cnet = 1 + 12 = 13 F

Posted on 26 Nov 2024, this text provides information on General Knowledge related to General Awareness in General Knowledge. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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