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LoginAmbiguity in array of 2d arrays declaration in C
General Tech Bugs & Fixes 3 years ago
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Answers (2)
manpreet 3 years ago
No, it won't work. Because these declarations declare different types which are incompatible.
unsigned char (*data)[2][2]: declare data as pointer to array 2 of array 2 of unsigned char
+---+ +---+---+
| -+----->| | |
+---+ +---+---+
data | | |
+---+---+
unsigned char [2][2]
unsigned char *data[2][2]: declare data as array 2 of array 2 of pointer to unsigned char
+---+---+
unsigned char <---+- | -+---> unsigned char
+---+---+
unsigned char <---+- | -+---> unsigned char
+---+---+
data
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manpreet![Tuteehub forum best answer]()
Best Answer
3 years ago
I'm going through a code where I encountered this line of code. I'm not able to understand
unsigned char (*data)[int][int]declared as argument in the function, if I consider this piece of code as an array of two-dimensional arrays(I'm passing array of 2d arrays) and then if I modify the code asunsigned char *data[int][int]should this not work?.