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General Tech Bugs & Fixes 2 years ago
Posted on 16 Aug 2022, this text provides information on Bugs & Fixes related to General Tech. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.
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i have the following json output
"lc_facts": { "changed": false, "failed": false, "launch_configurations": [ { "block_device_mappings": [ { "device_name": "/dev/sda1", "ebs": { "delete_on_termination": true, "volume_size": 40, "volume_type": "gp2" } } ] } ] }
The query below
- debug: msg: "{{ lc_facts.launch_configurations|json_query('[*].block_device_mappings[0].ebs.[volume_size]') | flatten }}"
gives
"msg": [ [40] ]
i want to convert into an integer so i can use this value. i tried everything, but all i want is to get number only without brackets. i also added |int in the end, but it gives me 0 value, which is weird.
|int
please help, i am really in trouble.
Brackets create a list. "[[40]]" is a list of lists">lists with one element "40". The play below
vars: var1: [[40]] tasks: - debug: var=var1 - debug: var=var1[0] - debug: var=var1[0][0]
gives:
"var1": [ [ 40 ] ] "var1[0]": [ 40 ] "var1[0][0]": "40"
def dict_to_obj(obj, data): for d in data: if isinstance(data[d], dict): setattr(obj, str(d), obj.__class__()) dict_to_obj(getattr(obj, str(d)), data[d]) else: setattr(obj, str(d), data[d]) return obj class Empty:pass obj = Empty() obj = dict_to_obj(obj,Your_JSON_object) #Now here you get all json attributes as objects e.g. #to get volume_size : print(obj.lc_facts.launch_configurations.block_device_mappings.ebs.volume_size) # but for this to work, you need to restructure your json nested key-value pairs like # this :- "launch_configuration" : {....} # instead of this :- "launch configuration" : [ {....} ]
I hope this helps.
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