Google Maps Javascript and PHP

General Tech Bugs & Fixes 2 years ago

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Posted on 16 Aug 2022, this text provides information on Bugs & Fixes related to General Tech. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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manpreet Tuteehub forum best answer Best Answer 2 years ago

 

I try to make a menu bar with icons which show the same icons in the map when clicked, for example hotels or bars.

I made a form with radio buttons for choose and click submit. This goes to PHP, connects to PostgreSQL, executes the query, and returns a result. It is not good solution though, because I want the user click on a icon to dynamically show the icons in map without any need to click on a submit button.

Is it possible, does an example exist?

I try to make it with jQueries and AJAX i make a jQuery which if i click show a alert massage i try to put the AJAX conection to return the JSONarray but is not make anythin This is a snapshot of php and javascript code. PHP conectin database make fetch

insert  data in array with this line of code

if($type=="warning"){

while ($row = pg_fetch_array($result,null, PGSQL_ASSOC)) {

        $row_array['gid'] = $row['gid'];
        $row_array['cause'] = $row['cause'];
        $row_array['duration'] = $row['duration'];
        $row_array['image'] = $row['image'];
            $row_array['km'] = $row['km'];
        $row_array['coords'] = json_decode($row['geom'], true);

        array_push($json_response,$row_array);
    }
}
   echo $json_response; 

JavaScript code

$(document).ready(function(){
                $(".warning").click(function(event){
                    $.ajax({
                        url: 'php/ajax-follow.php',
                        type: 'post',
                        data: {'type': 'warning'},
                        dataType: 'json',
                        success: function(data) {
                            imgAr = JSON.parse($json_response);
                            alert(imgAr);
                        },
                        error: function(xhr, desc, err) {
                            console.log(xhr);
                            console.log("Details: " + desc + "\nError:" + err);
                        }
                    });
                });
            });

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