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General Tech Bugs & Fixes 2 years ago
Posted on 16 Aug 2022, this text provides information on Bugs & Fixes related to General Tech. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.
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I would like to use a QQueue to store objects of my class. The class has members that are pointers to QPoints. I store an object of my class in a QQueue and retrieve it.
#include <QQueue> #include <QPoint> #include <QDebug> class Foo { public: Foo(int x, int y); ~Foo(); QPoint bar; QPoint* baz; //Q_DISABLE_COPY(Foo) // not sure whether I need this }; Foo::Foo(int x, int y): bar(x, y) { baz = new QPoint(x, y); } Foo::~Foo() { delete this->baz; } int main(void) { QQueue<Foo> queue; Foo a(5, 6); qDebug() << "a.bar.x()=" << a.bar.x() << ", a.baz->x()=" << a.baz->x(); queue.enqueue(a); Foo b = queue.dequeue(); qDebug() << "b.bar.x()=" << b.bar.x() << ", b.baz->x()=" << b.baz->x(); return 0; }
Output:
a.bar.x()= 5 , a.baz->x()= 5 b.bar.x()= 5 , b.baz->x()= 0 09:46:59: The program has unexpectedly finished.
If I comment out delete this->baz; in the destructor I get what I would have expected:
delete this->baz;
a.bar.x()= 5 , a.baz->x()= 5 b.bar.x()= 5 , b.baz->x()= 5
Could someone explain what's going on here? It seems to me that the destructor to Foo is being called early. Thanks.
QQueue stores a copy of the added object. So, at this line Foo b = queue.dequeue(); destructor of Foo is called. You can ensure in this in debugger. Add breakpoint to Foo destructor and debug.
QQueue
Foo b = queue.dequeue();
Foo
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