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Take A QuizGeneral Tech Bugs & Fixes 2 years ago
Posted on 16 Aug 2022, this text provides information on Bugs & Fixes related to General Tech. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.
php
$mysqli = new mysqli("s://forum.tuteehub.com/tag/server">server", "username", "password", "database_name");
// TODO - Check that connection was successful.
$unsafe_variable = $_POST["user-input"];
$stmt = $mysqli->s://forum.tuteehub.com/tag/prepare">prepare("INSERT INTO table (s://forum.tuteehub.com/tag/column">column) VALUES (?)");
// TODO check that $stmt creation succeeded
// "s" means the database expects a string
$stmt->bind_param("s", $unsafe_variable);
$stmt->execute();
$stmt->close();
$mysqli->close();
?>
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manpreet
Best Answer
2 years ago
If user input is inserted without modification into an SQL query, then the application becomes vulnerable to SQL injection, like in the following example:
That's because the user can input something like
value'); DROP TABLE table;--
, and the query becomes:What can be done to prevent this from happening?