How do I turn a string number into an int array of the individual digits

manpreet Best Answer 2 years ago

I have 20 digit strings ex: 12345678912345678912. I want to turn this into an array of ints [1,2,3...2] How would I do that? (I kept getting errors with sstream, atoi/stoi)

manpreet 2 years ago

Create a new array, and convert each number character to number. Just subtract '0' from the number character and you will get the number.

The number character - '0' = the ASCII value of that character - the ASCII value of '0' = the number.

std::vector<int> digits;
for (int i = 0; i < s.size(); i++)
    digits.push_back(s[i] - '0');