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General Tech Bugs & Fixes 2 years ago
Posted on 16 Aug 2022, this text provides information on Bugs & Fixes related to General Tech. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.
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I need find a string which already has special chars removed. So, I want to do is to find that string in a sentence and return the string with special chars. Ex: string = France09
string = France09
Sentence : i leaved in France'09.
now I did re.search('France09',sentence), it will return True or False. But I want to get the output as France'09.
re.search('France09',sentence)
True
False
France'09
Can any one help me.
From the docs (https://docs.python.org/2/library/re.html#re.search), search is not returning True or False:
Scan through string looking for the first location where the regular expression pattern produces a match, and return a corresponding MatchObject instance. Return None if no position in the string matches the pattern; note that this is different from finding a zero-length match at some point in the string.
you are creating a new set and assign it to x here
set
x
x = x | set([4, 5, 6])
from here on y is independent of x (they are the names of different sets).
y
on the other hand in-place assignment in your first example does not create a new set; it just modifies the current instance in
x |= set([4, 5, 6])
now y still refers to the same set as x. you can see the difference by printing
print(id(x)) print(id(y))
before and after the assignments.
it may be instructive to visualize the difference on pythontutor.com.
everything i said above is valid for mutable objects (e.g. sets). for immutable objects the in-place assignments behave just like the 'normal' assignments; i.e. for x an int: x += 1 is the same as x = x + 1.
int
x += 1
x = x + 1
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