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General Tech Bugs & Fixes 2 years ago
Posted on 16 Aug 2022, this text provides information on Bugs & Fixes related to General Tech. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.
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I am sending an Ajax POST request to Django from a Javascript modal. The csrf token is included correctly (after much headache...) but for whatever reason, I cannot 'fetch' the request data in my views.py. I have added some comments in the code to indicate what seems to be working
I have been reading everything I could find on this, but still couldn't find the error so any input would be highly appreciated. Thanks!
function getMenuItem(id){ console.log(id); // menuitem id prints correctly // Open request to get menuitem const request = new XMLHttpRequest(); request.open('POST', '/menuitem'); // Include csrf token in header so Django will accept the request const header = "X-CSRFToken" const token = Cookies.get('csrftoken'); // Using the js-cookie library console.log(token); // token prints correctly request.setRequestHeader(header, token); // Send request request.send(id); //Once request is received parse it and insert result in DOM request.onload = () => { const received = request.responseText; console.log(received); // Prints the debug message from Django const parsed = JSON.parse(received); document.getElementById('menuItem').innerHTML = parsed; }; };
def menuitem(request): if request.method == 'POST': id = request.body # I have also tried HttpRequest.body print(id) # Does not print menuitem = MenuConfiguration.objects.filter(id=id).all() menuitem = serializers.serialize('json', menuitem) menuitem = json.loads(menuitem) return menuitem
Traceback (most recent call last): File "/Library/Frameworks/Python.framework/Versions/3.7/lib/python3.7/site-packages/django/core/handlers/exception.py", line 34, in inner response = get_response(request) File "/Library/Frameworks/Python.framework/Versions/3.7/lib/python3.7/site-packages/django/utils/deprecation.py", line 93, in __call__ response = self.process_response(request, response) File "/Library/Frameworks/Python.framework/Versions/3.7/lib/python3.7/site-packages/django/middleware/clickjacking.py", line
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