Jackson deserialization error: MismatchedInputException

General Tech Bugs & Fixes 2 years ago

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Posted on 16 Aug 2022, this text provides information on Bugs & Fixes related to General Tech. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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manpreet Tuteehub forum best answer Best Answer 2 years ago

I have the following class

public class Cart {
    private final String id;

    public Cart(String id) { this.id = id;}

    public String getId() { return id; }
}

And the following test:

    String jsonString = "{\"id\":\"56c7b5f7-115b-4cb9-9658-acb7b849d5d5\"}";
    Cart cart = mapper.readValue(jsonString, Cart.class);
    assertThat(cart.getId()).isEqualTo("56c7b5f7-115b-4cb9-9658-acb7b849d5d5");

And I'm getting the following error:

com.fasterxml.jackson.databind.exc.MismatchedInputException: Cannot construct instance ofcom.store.domain.model.Cart (although at least one Creator exists): cannot deserialize from Object value (no delegate- or property-based Creator) at [Source: (String)"{"id":"56c7b5f7-115b-4cb9-9658-acb7b849d5d5"}"; line: 1, column: 2]

I can't figure out what's wrong here. Any help please?

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manpreet 2 years ago

You should add a normal constructor without any params like this:

public Cart() { }

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