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General Tech Bugs & Fixes 2 years ago
Posted on 16 Aug 2022, this text provides information on Bugs & Fixes related to General Tech. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.
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There is a table messages that contains data as shown below:
messages
Id Name Other_Columns ------------------------- 1 A A_data_1 2 A A_data_2 3 A A_data_3 4 B B_data_1 5 B B_data_2 6 C C_data_1
If I run a query select * from messages group by name, I will get the result as:
select * from messages group by name
1 A A_data_1 4 B B_data_1 6 C C_data_1
What query will return the following result?
3 A A_data_3 5 B B_data_2 6 C C_data_1
That is, the last record in each group should be returned.
At present, this is the query that I use:
SELECT * FROM (SELECT * FROM messages ORDER BY id DESC) AS x GROUP BY name
But this looks highly inefficient. Any other ways to achieve the same result?
CREATE TABLE `posts` ( `PostId` bigint(20) unsigned NOT NULL auto_increment, `PostTypeId` bigint(20) unsigned NOT NULL, `AcceptedAnswerId` bigint(20) unsigned default NULL, `ParentId` bigint(20) unsigned default NULL, `CreationDate` datetime NOT NULL, `Score` int(11) NOT NULL default '0', `ViewCount` int(11) NOT NULL default '0', `Body` text NOT NULL, `OwnerUserId` bigint(20) unsigned NOT NULL, `OwnerDisplayName` varchar(40) default NULL, `LastEditorUserId` bigint(20) unsigned default NULL, `LastEditDate` datetime default NULL, `LastActivityDate` datetime default NULL, `Title` varchar(250) NOT NULL default '', `Tags` varchar(150) NOT NULL default '', `AnswerCount` int(11) NOT NULL default '0', `CommentCount` int(11) NOT NULL default '0', `FavoriteCount` int(11) NOT NULL default '0', `ClosedDate` datetime default NULL, PRIMARY KEY (`PostId`), UNIQUE KEY `PostId` (`PostId`), KEY `PostTypeId` (`PostTypeId`), KEY `AcceptedAnswerId` (`AcceptedAnswerId`), KEY `OwnerUserId` (`OwnerUserId`
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