Return the next 50 characters after a string is found in a file

manpreet Best Answer 2 years ago

I'm pretty terrible with regex and searching for patterns, so I don't really know where to start.

I need to find  in test.txt and return the next 50 characters after it. It's for bash script, so other languages will just be a pain.

manpreet 2 years ago

I dont know if it's the best idea">idea to parse html like you are trying to, but anyways, this works, if you have linebreaks, if you dont, you can remove the tr part :

cat yourFile.html | tr -d '\n' | awk -F'id="latest_button">' '{print $2}' | cut -c -50

So, tr will get rid of the linebreaks, to treat everything as one line string.

awk -F sets the delimiter to the tag, print $2 , prints the part after the delimiter

and cut -c -50 prints only the first 50 chars