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Take A QuizGeneral Tech Bugs & Fixes 3 years ago
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You can try like this:
Sample Data:
create table customer(customer_id integer, customer_name varchar(20));
create table purchaser(purchaser_id varchar(20), customer_id integer, description varchar(20));
insert into customer values(1, 'Marg');
insert into customer values(2, 'Ben');
insert into customer values(3, 'Phil');
insert into customer values(4, 'Steve');
insert into purchaser values(1, 2, '500 Reams');
insert into purchaser values(2, 3, '6 toners');
insert into purchaser values(3, 3, '20 Staplers');
insert into purchaser values(4, 3, '20 Staplers');
insert into purchaser values(5, 3, '20 Staplers');
SELECT c.customer_id, c.customer_name, COUNT(p.purchaser_id) AS number_of_purchaes
FROM customer c
LEFT JOIN purchaser p ON c.customer_id = p.customer_id
GROUP BY c.customer_id;
SQL fiddle: http://sqlfiddle.com/#!9/32ff0a/2
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manpreet
Best Answer
3 years ago
I want to display the number of purchases each customer has made. If they've made 0 purchases, I want to display 0.
Desired Output:
Customer Table:
Purchases Table:
My current query is as follows:
However, since it's a
LEFT JOIN, the query results in rows for customers with no purchases, which makes them part of theCOUNT(*). In other words, customers who've made 0 purchases are displayed as having made 1 purchase, like so:LEFT JOIN Output:
I've also tried an
INNER JOIN, but that results in customers with 0 purchases not showing at all:INNER JOIN Output:
How could I achieve my
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