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General Tech Bugs & Fixes 2 years ago
Posted on 16 Aug 2022, this text provides information on Bugs & Fixes related to General Tech. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.
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I am trying to run a while loop that runs when the input given is not equal to either "1" "2" or "3".
Below you can see the code:
string get_menu_choice() { string option; cout << "What action would you like to perform?" << endl; cout << "1. View a room." << endl << "2. Create a new room." << endl << "3. Delete a room." << endl; cout << "Enter your choice: "; cin >> option; while (option != "1" || option != "2" || option != "3") { cout << "Invalid input, enter in only 1, 2 or 3!" << endl; cout << "Enter your choice: "; cin >> option; } return option; };
When I run this, it doesn't accept 1, 2 or 3 as an acceptable answer and keeps looping through
I have tried changing the statement to while(options != ("1" || "2" || "3")){//code here}however this also was unsuccessful for me.
while(options != ("1" || "2" || "3")){//code here}
you should code like below:
while(option != "1" && option != "2" && option != "3")
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