printf("%d\n", &Foo::c): this is undefined behavior, as &Foo::c is not an integer, but a pointer to member (but, actually, it is usual that the compiler stores pointer to data member as offset, and as 8 is the offset of Foo::c, 8 is printed).
std::cout << &Foo::c: this prints the value &Foo::c. As iostream doesn't have a pointer to member printer, it chooses the closest one: it converts it to bool, and prints it as integer. As &Foo::c converted to bool is true, 1 is printed.
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Best Answer
3 years ago
I tried the following code of C++. However, the outputs of
intf">printfandstd::b.com/tag/cout">coutare different. Can someone tell me why?