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Take A QuizGeneral Tech Bugs & Fixes 2 years ago
Posted on 16 Aug 2022, this text provides information on Bugs & Fixes related to General Tech. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.
The group defined by (..)
is Group 1. The +
quantifier repeats it. Every time the engine is able to repeat the group (matching two characters), Group 1 gets overwritten.
aa
to Group 1bb
to Group 1cc
to Group 1.When you inspect Group 1, the engine returns cc
. All other captures are lost.
(The exception is the .NET engine, which also returns cc
but also allows you to inspect intermediate captures thanks to the CaptureCollection object. It would contain aa
, bb
and cc
.)
With (..)+(...)
, Why does Group 1 Contain aa
? Backtracking!
To understand this, we again need to follow the path of the regex engine.
aa
to Group 1(..)
group and captures bb
to Group 1(..)
group and captures cc
to Group 1(...)
. It fails: there are no characters left to consume.+
means one or more times, and we matched ..
three times, so we can give one up, or even two. At this stage, the engine gives up the last match of the quantified (..)+
group, which is cc
. We are back to when Group 1 was bb
.(...)
again. There are only two characters left: cc
, so it fails again.(..)+
group, which is bb
. At this stage, Group 1 is aa
again.(...)
again. It succeeds: Group 2 is bbc
, and Group 1 is aa
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manpreet
Best Answer
2 years ago
Can someone explain why following returns 'cc'?
I was told that because it put each match into group(1), so the last match is 'cc'. Is that true?
Then how to explain following?