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Why doesn't logical OR work with error throwing in JavaScript?

General Tech Bugs & Fixes 2 years ago

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Posted on 16 Aug 2022, this text provides information on Bugs & Fixes related to General Tech. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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manpreet Tuteehub forum best answer Best Answer 2 years ago

This is a pretty common and useful practice:

// default via value
var un = undefined
var v1 = un || 1

// default via a function call
var myval = () => 1
var v2 = un || myval()

But it doesn't work (SyntaxError) when throwing an error:

var v3 = un || throw new Error('un is not set!')

Is there a way how to achieve the same effect in a similarly elegant way? This is IMHO a lot of boilerplate code:

if (!un) {
    throw new Error('un is not set!')
}
var v3 = un

Or is there any theoretical obstruction, why this is not, and never will be, possible?

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