Here is a small sample program which counts up to 100 in increments of 10.
I use both std::cout and printf to display the value of list in each increment.
Comments added to hopefully help aid you in learning
#include dio>
int main()
{
int r = 10;
int list=0;
while (list < 100)
{
list += r; // this is the same as saying list = list + r, but is more succinct
std::cout << list << "\t"; // cout is in the std namespace, so you have to prefix with std::
printf("%d\n", list); // the printf format specified for int is "%d"
}
}Output:
10 10 20 20 30 30 40 40 50 50 60 60 70 70 80 80 90 90 100 100
Please note that I didn't use using namespace std; at the top to import cout into the global namespace. IMHO this is bad practice, so I typically will prefer std::cout etc.
manpreet![Tuteehub forum best answer]()
Best Answer
3 years ago
I am new learning C++ and I have basic questions and basic troubles :(
I want to print a list of numbers that are coming from the next following while condition:
I want to use printf instead of cout (because I still don´t know why with cout is not working).
Can anyone help me to give me the analogous printf command to
Thanks a lot!!!