how to print a list of numbers using printf in C++?

Here is a small sample program which counts up to 100 in increments of 10.

I use both std::cout and printf to display the value of list in each increment.

Comments added to hopefully help aid you in learning

#include 
#include dio>

int main()
{
    int r = 10;

    int list=0;
    while (list < 100)
    {
        list += r;                 // this is the same as saying list = list + r, but is more succinct

        std::cout << list << "\t"; // cout is in the std namespace, so you have to prefix with std::

        printf("%d\n", list);      // the printf format specified for int is "%d"
    }
}

Output:

10    10
20    20
30    30
40    40
50    50
60    60
70    70
80    80
90    90
100   100

Please note that I didn't use using namespace std; at the top to import cout into the global namespace. IMHO this is bad practice, so I typically will prefer std::cout etc.