Word count - ignoring/subtracting double spaces

manpreet Best Answer 2 years ago

I'm trying to learn some coding to broaden my scope of knowledge, and I've seemed to run into a bit of a conundrum.

I'm trying to create a program to output the number of characters, digits, punctuation, spaces, words and lines that are being read in from a file.

Here is the text file I am reading in.

  See Jack run. Jack can run fast. Jack runs after the cat. The cat's fur is black. See Jack catch the cat.
  Jack says, "I caught the cat."
  The cat says, "Meow!"
  Jack has caught 1 meowing cat. Jack wants 5 cats, but can't find any more.

Here is my code

  #include 
  #include 

  using namespace std;

  int main()
  {
  ifstream lab3;
  string word;
  lab3.open("lab3.txt");
  int countletters=0,countnum=0,countpunc=0,countspace=0,words=0,line=0;
  char character;
  if(!lab3)
  {
  cout << "Could not open file" << endl;
  return 1;
  }
  while(lab3.get(character) && !lab3.eof())
  {
  if(isalpha(character))
  {
  countletters++;
  }
  if (isdigit(character))
  {
  countnum++;
  }
  if (ispunct(character))
  {
  countpunc++;
  }
  if (isspace(character))
  {
  countspace++;
  }
  if (isalpha(character) && (isspace(character++) || ispunct(character++)))
  {
  words++;
  }
  if(character=='\n')
  {
  line++;
  }
  }
  cout << "There are " << countletters << " letters." << endl;
  cout << "There are " << countnum << " numbers." << endl;
  cout << "There are " << countpunc << " punctuations." << endl;
  cout 
                                                

                                                                                                        
                                                    
                                                
                                                

                                                    

                                                        
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