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General Tech QA/Testing 2 years ago
Posted on 16 Aug 2022, this text provides information on QA/Testing related to General Tech. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.
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Will this work for testing whether a value at position "index" exists or not, or is there a better way:
if(arrayName[index]==""){ // do stuff }
All arrays in JavaScript contain array.length elements, starting with array[0] up until array[array.length - 1]. By definition, an array element with index i is said to be part of the array if i is between 0 and array.length - 1 inclusive.
array.length
array[0]
array[array.length - 1]
i
0
array.length - 1
That is, JavaScript arrays are linear, starting with zero and going to a maximum, and arrays don't have a mechanism for excluding certain values or ranges from the array. To find out if a value exists at a given position index (where index is 0 or a positive integer), you literally just use
if (index < array.length) { // do stuff }
However, it is possible for some array values to be null, undefined, NaN, Infinity, 0, or a whole host of different values. For example, if you add array values by increasing the array.lengthproperty, any new values will be undefined.
undefined
NaN
Infinity
To determine if a given value is something meaningful, or has been defined. That is, not undefined, or null:
null
if (typeof array[index] !== 'undefined') {
or
if (typeof array[index] !== 'undefined' && array[index] !== null) {
Interestingly, because of JavaScript's comparison rules, my last example can be optimised down to this:
if (array[index] != null) { // The == and != operators consider null equal to only null or undefined }
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