I would use filter
:
str_list = filter(None, str_list) # fastest
str_list = filter(bool, str_list) # fastest
str_list = filter(len, str_list) # a bit slower
str_list = filter(lambda item: item, str_list) # slower than list comprehension
Python 3 returns an iterator from filter
, so should be wrapped in a call to list()
str_list = list(filter(None, str_list)) # fastest
(etc.)
Tests:
>>> timeit('filter(None, str_list)', 'str_list=["a"]*1000', number=100000)
2.4797441959381104
>>> timeit('filter(bool, str_list)', 'str_list=["a"]*1000', number=100000)
2.4788150787353516
>>> timeit('filter(len, str_list)', 'str_list=["a"]*1000', number=100000)
5.2126238346099854
>>> timeit('[x for x in str_list if x]', 'str_list=["a"]*1000', number=100000)
13.354584932327271
>>> timeit('filter(lambda item: item, str_list)', 'str_list=["a"]*1000', number=100000)
17.427681922912598
manpreet
Best Answer
2 years ago
I want to remove all empty strings from a list of strings in python.
My idea looks like this:
Is there any more pythonic way to do this?