HEAT transfer rate per unit time, h = CONVECTIVE heat transfer coefficient, A = exposed surface area, ΔT = change in TEMPERATURE. Calculation:Given:A = 0.09 M2, Q = 600 watts, h = 285.3 W/m2-deg CLet, Tw = Water temperature, Ts = surface temperature.∴ ΔT = (Ts - Tw)Substituting all the values inQ = h × A × ΔT = h × A × (Ts - Tw) 600 = 285.3 × 0.09 × (Ts - 37)∴ Surface temperature of the heater is,Ts = \(\FRAC{{600}}{{283.5 \times 0.09}} + 37\)Ts = 60.5°C