Which species will most readily act as the reducing agent in becoming Mn²?​

RiaElidaMF RiaElidaMF Best Answer 1 year ago

king the changes that occur in their oxidation numbers, we see that Cl− is the reducing agent, and MnO2 is the oxidizing agent.Explanation:The simplest way to determine the reducing agent (or the oxidizing agent for that mattter) is to determine the oxidation number of each atom in the equation.By the way, I think the equation you have given should have the second substance written as H+ rather than just H . FREE hydrogen atoms do not exist in aqueous solution, but hydrogen ions do.So, we will focus on the Mn atoms and the Cl atoms as these will have changes in their oxidation numbers.In MnO2 , since we assign -2 as the VALUE of the two OXYGEN atoms, and since the total of the oxidation numbers must be ZERO (the real charge on the formula), the Mn atom has a value of +4.In the Cl− ion, the oxidation number is the real charge, -1.Looking at the products, the Mn2+ ion now has oxidation number +2. This decrease in the oxidation number tells us that the Mn atom has been reduced. Therefore, the compound in which it is FOUND (MnO2) is the oxidizing agent!At the same time, the chlorine atom increases to an oxidation number of zero (in its element form as Cl2 ). The increase in oxidation number means the Cl− ion has been oxidized, and so, must be the reducing agent.

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