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Login3 The sides of a quadrilateral, taken in order are 5, 12, 14 and 15 metres respectively, andthe angle contained by the first two sides is a right angle. Find its area.
Interview Questions Math 1 year ago
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JohkalSA JohkalSA![Tuteehub forum best answer]()
Best Answer
1 year ago
Step-by-step explanation:Here, AB = 5 m, BC = 12 m, CD = 14 m and DA = 15 m Join the diagonal AC. Now, area of △ABC = 1/2 x AB x BC = 1/2 x 5 x 12 = 30 Area of △ABC is 30 M2 In △ABC, (RIGHT triangle). From Pythagoras theorem, AC2 = AB2 + BC2 AC2 = 52 + 122 AC2 = 25 + 144 = 169 or AC = 13 Now in △ADC, All sides are know, APPLY Heron’s Formula: Where a, b and c are sides of a triangle. PERIMETER of △ADC = 2s = AD + DC + AC 2s = 15 m + 14 m + 13 m s = 21 m Area of △ADC = 84 m^2 Area of quadrilateral ABCD = Area of △ABC + Area of △ADC = (30 + 84) m2 = 114 m^2Hope it helps!
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