A, B, C are three cups having capacities of 120, 180 and 200 cc respectively which are completely filled with 211tea of three different varieties. They are all mixed in a separate vessel of capacity more than that of A, B, Ctaken together, and then the mixture is poured successively into A, B, C. Then how much (in cc) of A and B'stea will be there in C?​

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- A, B, C are three cups having capacities of 120, 180 and 200 cc respectively which are completely filled with tea of three different varieties. They are all mixed in a separate vessel of capacity more than that of A, B, C taken together, and then the mixture is poured successively into A, B, C. Then how much (in cc) of A and B's tea will be there in C ?Solution :- given that, all cup are completely filled with tea of three different varieties. So,→ Tea in cup A = 120cc→ Tea in cup B = 180cc→ Tea in cup C = 200cc now, all three cups mixed in a separate vessel . Than, → Ratio of varieties of tea in vessel = A : B : C = 120 : 180 : 200 = 6 : 9 : 10 . Now, again the mixture is poured successively into A, B, C. Than, we can conclude that, Now, mixture has Ratio of varieties of tea in 6 : 9 : 10. Therefore, → In C , QUANTITY of A = 200 * (6/25) = 48 cc. → In C, quantity of B = 200 * (9/25) = 72 cc. Hence, quantity of A and B in C are 48 cc and 72 cc respectively . LEARN more :- A sum of r is divided between A,B,C and D such that the ratio of shares of A and B is 9:5, C's shareis 70% of B's share... brainly.in/question/26251723Gopi gave 30% of the MONEY he had to his parents,one-third of the money now left was spent for his pdeposited in the b... brainly.in/question/26795559

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