Q. 10. The length, breadth and height of a room are 8 m 50 cm, 6 m 25 cm and 4 m 75 cm respectively. Findthe length of the longest rod that can measure thedimensions of the room exactly(In this question we should find HCF) can anyone say why we should find hcf ​

RiaElidaMF RiaElidaMF Best Answer 1 year ago

-STEP EXPLANATION:The given dimensions are 825CM, 675CM & 450cm.The given dimensions are 825cm, 675cm & 450cm.Now to find the length of room we need a common factor of 825,675,450The given dimensions are 825cm, 675cm & 450cm.Now to find the length of room we need a common factor of 825,675,450Using PRIME factorization:The given dimensions are 825cm, 675cm & 450cm.Now to find the length of room we need a common factor of 825,675,450Using Prime factorization:825=3×5 The given dimensions are 825cm, 675cm & 450cm.Now to find the length of room we need a common factor of 825,675,450Using Prime factorization:825=3×5 2The given dimensions are 825cm, 675cm & 450cm.Now to find the length of room we need a common factor of 825,675,450Using Prime factorization:825=3×5 2 ×11The given dimensions are 825cm, 675cm & 450cm.Now to find the length of room we need a common factor of 825,675,450Using Prime factorization:825=3×5 2 ×11675=3 The given dimensions are 825cm, 675cm & 450cm.Now to find the length of room we need a common factor of 825,675,450Using Prime factorization:825=3×5 2 ×11675=3 2The given dimensions are 825cm, 675cm & 450cm.Now to find the length of room we need a common factor of 825,675,450Using Prime factorization:825=3×5 2 ×11675=3 2 ×5 The given dimensions are 825cm, 675cm & 450cm.Now to find the length of room we need a common factor of 825,675,450Using Prime factorization:825=3×5 2 ×11675=3 2 ×5 2The given dimensions are 825cm, 675cm & 450cm.Now to find the length of room we need a common factor of 825,675,450Using Prime factorization:825=3×5 2 ×11675=3 2 ×5 2 The given dimensions are 825cm, 675cm & 450cm.Now to find the length of room we need a common factor of 825,675,450Using Prime factorization:825=3×5 2 ×11675=3 2 ×5 2 450=2×3 The given dimensions are 825cm, 675cm & 450cm.Now to find the length of room we need a common factor of 825,675,450Using Prime factorization:825=3×5 2 ×11675=3 2 ×5 2 450=2×3 2The given dimensions are 825cm, 675cm & 450cm.Now to find the length of room we need a common factor of 825,675,450Using Prime factorization:825=3×5 2 ×11675=3 2 ×5 2 450=2×3 2 ×5 The given dimensions are 825cm, 675cm & 450cm.Now to find the length of room we need a common factor of 825,675,450Using Prime factorization:825=3×5 2 ×11675=3 2 ×5 2 450=2×3 2 ×5 2The given dimensions are 825cm, 675cm & 450cm.Now to find the length of room we need a common factor of 825,675,450Using Prime factorization:825=3×5 2 ×11675=3 2 ×5 2 450=2×3 2 ×5 2 The given dimensions are 825cm, 675cm & 450cm.Now to find the length of room we need a common factor of 825,675,450Using Prime factorization:825=3×5 2 ×11675=3 2 ×5 2 450=2×3 2 ×5 2 Now from aboveThe given dimensions are 825cm, 675cm & 450cm.Now to find the length of room we need a common factor of 825,675,450Using Prime factorization:825=3×5 2 ×11675=3 2 ×5 2 450=2×3 2 ×5 2 Now from aboveHCF=3×5 The given dimensions are 825cm, 675cm & 450cm.Now to find the length of room we need a common factor of 825,675,450Using Prime factorization:825=3×5 2 ×11675=3 2 ×5 2 450=2×3 2 ×5 2 Now from aboveHCF=3×5 2The given dimensions are 825cm, 675cm & 450cm.Now to find the length of room we need a common factor of 825,675,450Using Prime factorization:825=3×5 2 ×11675=3 2 ×5 2 450=2×3 2 ×5 2 Now from aboveHCF=3×5 2 =75The given dimensions are 825cm, 675cm & 450cm.Now to find the length of room we need a common factor of 825,675,450Using Prime factorization:825=3×5 2 ×11675=3 2 ×5 2 450=2×3 2 ×5 2 Now from aboveHCF=3×5 2 =75∴ The length of longest rod to measure the length of room is 75cm.

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