FCC                    \[4R=\SQRT{2}a\]                    \[a=\frac{4r}{\sqrt{2}}\]

"> FCC                    \[4R=\SQRT{2}a\]                    \[a=\frac{4r}{\sqrt{2}}\]

">
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In face centred cubic unit cell edge length is        [DPMT 2005]

Joint Entrance Exam - Main (JEE Main) Chemistry in Joint Entrance Exam - Main (JEE Main) 1 year ago

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In FCC                    \[4R=\SQRT{2}a\]                    \[a=\frac{4r}{\sqrt{2}}\]

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Posted on 14 Aug 2024, this text provides information on Joint Entrance Exam - Main (JEE Main) related to Chemistry in Joint Entrance Exam - Main (JEE Main). Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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