UNDERSET{(S)\,}{\mathop{{{A}^{2+}}}}\,+\underset{{{(2S)}^{2}}}{\mathop{2{{B}^{-}}}}\,\] \[{{K}_{SP}}=4{{S}^{3}}\]      \[S=\sqrt[3]{\FRAC{{{K}_{sp}}}{4}}=\sqrt[3]{\frac{4\times {{10}^{-12}}}{4}}\] \[=1\times {{10}^{-4}}\,\,gm.\,mol/litre\]

"> UNDERSET{(S)\,}{\mathop{{{A}^{2+}}}}\,+\underset{{{(2S)}^{2}}}{\mathop{2{{B}^{-}}}}\,\] \[{{K}_{SP}}=4{{S}^{3}}\]      \[S=\sqrt[3]{\FRAC{{{K}_{sp}}}{4}}=\sqrt[3]{\frac{4\times {{10}^{-12}}}{4}}\] \[=1\times {{10}^{-4}}\,\,gm.\,mol/litre\]

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Solubility product for salt \[A{{B}_{2}}\] is \[4\times {{10}^{-12}}\]. Calculate solubility [RPET 2003]

Joint Entrance Exam - Main (JEE Main) Chemistry in Joint Entrance Exam - Main (JEE Main) 10 months ago

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\[A{{B}_{2}}\]⇌\[\UNDERSET{(S)\,}{\mathop{{{A}^{2+}}}}\,+\underset{{{(2S)}^{2}}}{\mathop{2{{B}^{-}}}}\,\] \[{{K}_{SP}}=4{{S}^{3}}\]      \[S=\sqrt[3]{\FRAC{{{K}_{sp}}}{4}}=\sqrt[3]{\frac{4\times {{10}^{-12}}}{4}}\] \[=1\times {{10}^{-4}}\,\,gm.\,mol/litre\]

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Posted on 25 Aug 2024, this text provides information on Joint Entrance Exam - Main (JEE Main) related to Chemistry in Joint Entrance Exam - Main (JEE Main). Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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