RMS}}=\sqrt{\frac{3RT}{M}}\]Þ \[{{V}_{rms}}=\sqrt{T}\]                    GIVEN \[{{V}_{1}}=V\], \[{{T}_{1}}=300K\], \[{{V}_{2}}=2V\], \[{{T}_{2}}=?\]                    \[\frac{{{V}_{1}}}{{{V}_{2}}}=\sqrt{\frac{{{T}_{1}}}{{{T}_{2}}}}\]; \[{{\left( \frac{V}{2V} \right)}^{2}}=\frac{300}{{{T}_{2}}}\] Þ \[{{T}_{2}}=300\times 4=1200K\]

"> RMS}}=\sqrt{\frac{3RT}{M}}\]Þ \[{{V}_{rms}}=\sqrt{T}\]                    GIVEN \[{{V}_{1}}=V\], \[{{T}_{1}}=300K\], \[{{V}_{2}}=2V\], \[{{T}_{2}}=?\]                    \[\frac{{{V}_{1}}}{{{V}_{2}}}=\sqrt{\frac{{{T}_{1}}}{{{T}_{2}}}}\]; \[{{\left( \frac{V}{2V} \right)}^{2}}=\frac{300}{{{T}_{2}}}\] Þ \[{{T}_{2}}=300\times 4=1200K\]

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The r.m.s. velocity of a certain gas is \[v\] at \[300K\]. The temperature, at which the r.m.s. velocity becomes double [Pb. CET 2002]

Joint Entrance Exam - Main (JEE Main) Chemistry in Joint Entrance Exam - Main (JEE Main) 11 months ago

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\[{{V}_{RMS}}=\sqrt{\frac{3RT}{M}}\]Þ \[{{V}_{rms}}=\sqrt{T}\]                    GIVEN \[{{V}_{1}}=V\], \[{{T}_{1}}=300K\], \[{{V}_{2}}=2V\], \[{{T}_{2}}=?\]                    \[\frac{{{V}_{1}}}{{{V}_{2}}}=\sqrt{\frac{{{T}_{1}}}{{{T}_{2}}}}\]; \[{{\left( \frac{V}{2V} \right)}^{2}}=\frac{300}{{{T}_{2}}}\] Þ \[{{T}_{2}}=300\times 4=1200K\]

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Posted on 01 Sep 2024, this text provides information on Joint Entrance Exam - Main (JEE Main) related to Chemistry in Joint Entrance Exam - Main (JEE Main). Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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