MOLE FRACTION  \[X=\frac{n}{n+N}\]\[=\frac{\frac{6}{60}}{\frac{6}{60}+\frac{180}{18}}=\frac{0.1}{10.1}\]. "> MOLE FRACTION  \[X=\frac{n}{n+N}\]\[=\frac{\frac{6}{60}}{\frac{6}{60}+\frac{180}{18}}=\frac{0.1}{10.1}\]. ">
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When \[6gm\] urea dissolve in \[180\,gm\,{{H}_{2}}O\]. The mole fraction of urea is                                               [CPMT 1988]

Joint Entrance Exam - Main (JEE Main) Chemistry in Joint Entrance Exam - Main (JEE Main) 11 months ago

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MOLE FRACTION  \[X=\frac{n}{n+N}\]\[=\frac{\frac{6}{60}}{\frac{6}{60}+\frac{180}{18}}=\frac{0.1}{10.1}\].
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