QUESTION , \[{{x}_{1}}=\frac{2+4+x}{3}\RIGHTARROW x=3{{x}_{1}}-6\] \[{{y}_{1}}=\frac{5-11+y}{3}\Rightarrow y=3{{y}_{1}}+6\] \[\therefore \] \[9(3{{x}_{1}}-6)+7(3{{y}_{1}}+6)+4=0\] Hence LOCUS is\[27x+21y-8=0\], which is parallel to 9x+7y+4 = 0.