0\LE {{\COS }^{-1}}{{x}_{i}}\le \pi ,\therefore {{\cos }^{-1}}{{x}_{i}}=0\] for all i. \[\therefore \]\[{{x}_{i}}=1\] for all \[i\therefore \sum\limits_{i=1}^{2n}{{{x}_{i}}=2n}\]

"> 0\LE {{\COS }^{-1}}{{x}_{i}}\le \pi ,\therefore {{\cos }^{-1}}{{x}_{i}}=0\] for all i. \[\therefore \]\[{{x}_{i}}=1\] for all \[i\therefore \sum\limits_{i=1}^{2n}{{{x}_{i}}=2n}\]

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If \[\sum\limits_{i=1}^{2n}{{{\cos }^{-1}}{{x}_{i}}=0}\] then \[\sum\limits_{i=1}^{2n}{{{x}_{i}}}\]is

Joint Entrance Exam - Main (JEE Main) Mathematics in Joint Entrance Exam - Main (JEE Main) 1 year ago

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[b] Since \[0\LE {{\COS }^{-1}}{{x}_{i}}\le \pi ,\therefore {{\cos }^{-1}}{{x}_{i}}=0\] for all i. \[\therefore \]\[{{x}_{i}}=1\] for all \[i\therefore \sum\limits_{i=1}^{2n}{{{x}_{i}}=2n}\]

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Posted on 27 Aug 2024, this text provides information on Joint Entrance Exam - Main (JEE Main) related to Mathematics in Joint Entrance Exam - Main (JEE Main). Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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